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Prelims GS-II (CSAT) · Numeracy · Arithmetic

Proportion

Proportion expresses equality between two ratios and provides a compact method for solving problems involving quantities that vary together. For CSAT, the essential skills are identifying the correct relationship, keeping units consistent, recognising fixed quantities and translating a word problem into an equation. Direct, inverse and compound proportion frequently appear within questions on work, speed, cost, consumption, maps and resource allocation.

1. Meaning, notation and core identities

A ratio compares two quantities through division. A proportion states that two such ratios are equal. Thus, 6 : 9 = 10 : 15 is a proportion because both ratios simplify to 2 : 3. Write the quantities in the same order on both sides: if the first ratio compares rice with wheat, the second must also compare rice with wheat.

For a : b = c : d, cross-multiplication gives ad = bc. This equality is the basic test of proportion and the quickest way to find a missing term. If 8 : 12 = x : 30, then 12x = 240 and x = 20. Alternatively, 12 becomes 30 by multiplication by 2.5, so 8 must become 20 by the same factor.

The fourth proportional to a, b and c is d such that a : b = c : d; hence d = bc/a. The third proportional to a and b is c such that a : b = b : c; hence c = b²/a. The mean proportional between positive quantities a and c is b = √(ac). For example, the mean proportional between 4 and 9 is 6.

Useful transformations include inversion, b/a = d/c, and alternation, a/c = b/d, whenever the denominators are non-zero. Componendo and dividendo gives (a + b)/(a − b) = (c + d)/(c − d), when defined. Use these identities selectively; cross-multiplication or a common multiplier is usually simpler.

  • Convert comparable quantities into common units before forming a dimensionless ratio: 1.5 metres : 75 centimetres = 150 : 75 = 2 : 1.
  • A rate can compare unlike units, such as kilometres per hour; retain the units consistently throughout the calculation.
  • If a : b = 3 : 5, write a = 3k and b = 5k rather than assuming that a and b equal 3 and 5.

2. Direct proportion and the unitary method

Two quantities are directly proportional when their ratio remains constant. If y = kx, doubling x doubles y and multiplying x by any factor multiplies y by the same factor. Examples include cost and quantity at a fixed unit price, distance and time at a fixed speed, and wages and hours at a fixed hourly rate.

The unitary method first finds the value corresponding to one unit and then scales it. If 8 notebooks cost ₹240, one notebook costs ₹30 and 15 notebooks cost ₹450. The equivalent proportional equation is 240/8 = C/15. Before using either approach, check that discounts, fixed charges or changing rates do not alter the relationship.

Direct proportion differs from a general increasing relationship. A taxi fare consisting of a ₹50 fixed charge plus ₹12 per kilometre increases with distance but is not directly proportional to distance. For 5 kilometres the fare is ₹110; for 10 kilometres it is ₹170, not ₹220. The fixed component prevents a constant fare-to-distance ratio.

  • A direct-proportion graph is a straight line through the origin.
  • Percentage scaling is proportional: a 20% increase multiplies a quantity by 1.20.
  • When a total T is divided in the ratio m : n, the shares are Tm/(m + n) and Tn/(m + n).

From word problem to proportional equation

  1. 1. Identify the unknown and the quantities being compared.
  2. 2. Convert relevant measurements to consistent units.
  3. 3. Identify fixed totals, rates and efficiency assumptions.
  4. 4. Choose direct, inverse or compound proportion.
  5. 5. Write the equation and simplify by cancellation.
  6. 6. Check direction, units and the answer against the conditions.

3. Inverse proportion and fixed-product reasoning

Two quantities are inversely proportional when their product remains constant. If xy = k, doubling x halves y. The identifying question is: what total is being held fixed? For a fixed journey, speed × time equals distance. For a fixed job performed by equally efficient workers, workers × days is constant when daily working hours are unchanged.

Suppose 12 workers complete a job in 15 days. The job requires 180 worker-days under the stated assumptions. With 20 equally efficient workers, the time becomes 180/20 = 9 days. Writing 12/20 = 15/D would incorrectly treat the relationship as direct. The reliable equation is 12 × 15 = 20 × D.

Inverse change is not an equal and opposite percentage change. If speed increases by 25%, it becomes 1.25 times its original value. For the same distance, time becomes 1/1.25 = 0.8 times the original time, a reduction of 20%. Similarly, a 20% speed reduction increases time by 25%. Reciprocal multipliers prevent this frequent error.

  • Equal worker efficiency and unchanged daily hours must be stated or reasonably implied.
  • Adding workers may not proportionately reduce real-world project time if tasks cannot be divided or coordination causes delays.
  • Food stock and duration are inversely related to the number of consumers only when consumption per person per day remains constant.
Recognising the appropriate proportional model
RelationshipConstant or ruleTypical applicationEssential condition
Directy/x = kCost and quantityFixed unit price without an additional fixed charge
Inversexy = kSpeed and travel timeFixed distance
CompoundOutput = k × workers × days × hoursWork and productionUniform efficiency and divisible work
SquareArea ratio = length ratio squaredSimilar figuresGeometric similarity
CubeVolume ratio = length ratio cubedSimilar solidsGeometric similarity

4. Compound proportion and related applications

Compound proportion involves more than two changing quantities. Express the underlying relationship before manipulating ratios. For uniform production, output is proportional to workers × days × hours per day × efficiency. Consequently, time is directly proportional to required output and inversely proportional to workers, daily hours and efficiency.

Suppose 12 workers working 6 hours daily complete 360 units in 5 days. How long will 15 equally efficient workers working 8 hours daily take to complete 720 units? Required days = 5 × (720/360) × (12/15) × (6/8) = 6 days. Each factor has a meaning: more output increases time, while more workers and longer working hours reduce it.

Map scales are another direct application. At a scale of 1 : 50,000, one centimetre on the map represents 50,000 centimetres, or 0.5 kilometre, on the ground. A map distance of 6 centimetres therefore represents 3 kilometres. The scale is a ratio of lengths, not areas.

For similar figures, areas vary as the square of corresponding lengths and volumes as the cube. If every length is multiplied by 3, area is multiplied by 9 and volume by 27. In mixtures, maintain the distinction between component ratios and fractions of the total: milk : water = 3 : 2 means milk forms 3/5, not 3/2, of the mixture.

  • In ratio chains, equalise the common term: A : B = 2 : 3 and B : C = 4 : 5 give A : B : C = 8 : 12 : 15.
  • When equal quantities are added to both terms of a ratio, the ratio generally changes; equal multiplication preserves it.
  • Use squared or cubed scale factors only when geometric similarity or the relevant formula justifies them.

5. CSAT problem-solving strategy and common traps

Begin by naming the unknown and recording the fixed conditions. Decide whether a constant ratio, constant product or a multi-factor relationship applies. This classification matters more than memorising a rule of three. A short equation often exposes information that is missing or irrelevant.

Predict the direction of change before calculating. More workers should require fewer days for the same work; a larger order should cost more at a fixed unit price. Cancel common factors before multiplying, and retain fractions until the final step. This reduces arithmetic effort and rounding errors.

Finally, check units, magnitude and the original condition. In multiple-choice questions, estimation can eliminate impossible answers, but it cannot replace choosing the correct relationship. When a price contains a fixed fee, efficiency changes, or demand varies unpredictably, ordinary direct or inverse proportion may not apply.

  • Do not confuse the ratio of two shares with either share's fraction of the total.
  • Do not assume that equal percentage increases and decreases cancel.
  • Do not mix minutes with hours, grams with kilograms or map centimetres with ground kilometres.
  • For successive changes, multiply scale factors rather than adding percentage changes.

Real-world case studies

PM POSHAN: scaling foodgrain requirements

PM POSHAN specifies foodgrain norms of 100 grams per child per school day at the primary level and 150 grams at the upper-primary level. For an illustrative group of 200 primary and 100 upper-primary children, the corresponding daily requirement is 20 + 15 = 35 kilograms. Requirements scale directly with children and feeding days within each category, but combining all children under one norm would be incorrect.

Survey of India maps: length versus area

Survey of India topographical maps include the 1 : 50,000 scale. At this scale, 1 centimetre represents 0.5 kilometre. A mapped rectangle measuring 4 centimetres by 2 centimetres corresponds approximately to 2 kilometres by 1 kilometre, giving a ground area of 2 square kilometres. This illustrates why an area conversion requires squaring the length conversion factor.

Previous year questions

No source-linked PYQ is available here yet. Use the practice questions below.

Practice questions

Practice MCQ 1 · Easy

If 1.2 metres : 80 centimetres = x : 18, what is the value of x?

  • A. 12
  • B. 27
  • C. 24
  • D. 30

Practice MCQ 2 · Easy

A shop sells 7.5 kg of rice for ₹450. If the price per kilogram remains unchanged and there are no additional charges, how much will 12 kg of rice cost?

  • A. ₹675
  • B. ₹750
  • C. ₹700
  • D. ₹720

Practice MCQ 3 · Easy

A grant of ₹9,600 is divided between two village libraries in the ratio 5 : 7. What is the smaller share?

  • A. ₹4,000
  • B. ₹4,800
  • C. ₹3,600
  • D. ₹5,600

Practice MCQ 4 · Easy

Eighteen equally efficient workers can complete a job in 20 days. How many days will 24 such workers take to complete the same job, working the same number of hours daily?

  • A. 12 days
  • B. 16 days
  • C. 15 days
  • D. 18 days

Practice MCQ 5 · Easy

A bus normally takes 150 minutes to cover a fixed route without stopping. If its speed throughout the route is increased by 20%, how long will it take?

  • A. 120 minutes
  • B. 125 minutes
  • C. 130 minutes
  • D. 135 minutes

Practice MCQ 6 · Moderate

Three districts A, B and C receive a total grant of ₹10,500. Their grants satisfy A : B = 3 : 4 and B : C = 6 : 7. What is district C's grant?

  • A. ₹3,000
  • B. ₹3,600
  • C. ₹4,500
  • D. ₹4,200

Practice MCQ 7 · Moderate

A map has a uniform scale of 1 : 50,000. A forest occupies an area of 12 square centimetres on the map. What is its actual area?

  • A. 0.3 square kilometre
  • B. 6 square kilometres
  • C. 3 square kilometres
  • D. 30 square kilometres

Practice MCQ 8 · Moderate

Sixteen workers, working 6 hours daily for 9 days, manufacture 432 identical components. How many days will 24 workers take to manufacture 720 such components if they work 8 hours daily and each has only 75% of the hourly productivity of a worker in the first group?

  • A. 10 days
  • B. 8 days
  • C. 12 days
  • D. 15 days

Practice MCQ 9 · Moderate

A taxi fare consists of a fixed charge and a charge directly proportional to distance. A journey of 8 km costs ₹146, while a journey of 14 km costs ₹218. What will a journey of 20 km cost under the same fare structure?

  • A. ₹280
  • B. ₹290
  • C. ₹300
  • D. ₹365

Practice MCQ 10 · Moderate

The quantities of grain in two warehouses are initially in the ratio 4 : 7. After 20 tonnes are added to the first warehouse and 10 tonnes are removed from the second, the ratio becomes 2 : 3. What was the initial total quantity of grain?

  • A. 330 tonnes
  • B. 400 tonnes
  • C. 450 tonnes
  • D. 440 tonnes

Practice MCQ 11 · Difficult

A relief camp has provisions sufficient for 240 persons for 50 days at a fixed daily ration per person. After 10 days, 60 more persons join, and the daily ration per person is reduced by 20%. After another 15 days, 90 persons leave. At that moment, additional provisions sufficient for 60 persons for 26 days at the original daily ration arrive, and the daily ration per remaining person is set at 90% of the original ration. Assuming no wastage or further changes, for how many days in total, counted from the opening of the camp, will the provisions last?

  • A. 60 days
  • B. 65 days
  • C. 70 days
  • D. 75 days

Practice MCQ 12 · Difficult

Thirty equally efficient workers, working 8 hours daily, are scheduled to complete a project in 24 days. After 8 days, the total amount of work required for the project is increased by 25% of the originally planned work. At the same time, 6 workers leave, and daily working hours are increased to 10. How many additional workers, each having 75% of an original worker's hourly efficiency, must join immediately to finish the enlarged project by the original deadline?

  • A. 8
  • B. 10
  • C. 12
  • D. 16

Practice MCQ 13 · Difficult

Two vessels P and Q initially contain milk and water in the ratios 3 : 2 and 1 : 4, respectively. Their initial mixture volumes are in the ratio 3 : 2. An equal volume of mixture is withdrawn from each vessel, and the withdrawn portions are exchanged. Both mixtures are stirred thoroughly before withdrawal and after exchange. Vessel P then contains equal quantities of milk and water. When 30 litres of pure milk are subsequently added to Q, it also contains equal quantities of milk and water. What was the initial volume of mixture in P?

  • A. 150 litres
  • B. 120 litres
  • C. 180 litres
  • D. 200 litres

Practice MCQ 14 · Difficult

A car is scheduled to complete a journey at a constant speed of 60 km/h without stopping. It actually covers the first 40% of the distance at 48 km/h, a second section at 72 km/h, and the remaining section at 96 km/h. The driving times for the second and third sections are in the ratio 2 : 1. Despite a total stoppage of 20 minutes, the car arrives exactly at its scheduled time. What is the total journey distance?

  • A. 300 km
  • B. 360 km
  • C. 480 km
  • D. 400 km

Practice MCQ 15 · Difficult

A factory uses machines of types A and B whose hourly production rates are in the ratio 3 : 2. Six A-machines and eight B-machines, operating for 5 hours, produce 1,360 usable components after 20% of the total output is rejected. For a new order, the hourly production rate of every A-machine is increased by 25%, while that of every B-machine remains unchanged. The factory uses eight B-machines during an 8-hour shift, but four of them each remain idle for 2 hours. If 10% of the total output in this shift is rejected, how many A-machines, each operating for the full 8 hours, are needed to produce exactly 3,168 usable components? Assume all stated rejection percentages apply exactly.

  • A. 6
  • B. 7
  • C. 8
  • D. 10

Further reading

  • NCERT Mathematics, Class VI: Ratio and Proportion.
  • NCERT Mathematics, Class VIII: Direct and Inverse Proportions.
  • UPSC official website: Civil Services Examination notification, syllabus and General Studies Paper II question papers.
  • Ministry of Education: PM POSHAN guidelines and foodgrain norms, pmposhan.education.gov.in.
  • Survey of India: official topographical mapping resources, surveyofindia.gov.in.

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